Question

An object is thrown vertically upwards with 20m/s.
Calulate time take
to reach high point by object
​

Answer 1

Answer:

incomplete question

Explanation:

you should give us the height also

Answer 2

Answer:

hey there is answer ...

I hope you help.....

Explanation:

Let us take the point of projection as the origin of coordinate system. Let the up direction be taken as positive.

The initial velocity of the body = + 20 m/s

Acceleration due to gravity a= - 10 m/s²

Let the time taken to return to the ground be t second

Since the objects return to the ground, the displacement s= 0 m

Using the relation; s = u × t + ½ a t².

Substituting various values

0 = 20 t - ½ × 10× t²; ==> 20 t - 5 t² = 0;

5 t² - 20 t = 0; ==> 5 t (t - 4) = 0; ==> t= 0 sec. or t = 4 sec.

The body would be at the ground at the beginning ie at t =0 and again at t = 4 s.

regards you

smart abhishek ........ !