Question

An object.Is thrown vertically upwards with a velocity 19.6m/s calculate distance and displacement after 3 s

Answer 1

Answer:

14.7 meter

Explanation:

s = ut - 1/2gt^2

= 19.6*3 - 1/2*9.8*9

= 58.8 - 44.1

= 14.7 meter

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Answer 2

Given

u = 19.6 m/s

t = 3s

a = -g = -9.8m/s

To Find

distance and displacement after 3 sec

Solution

w.k.t

S = ut + 1/2at²

s = (19.6)(3) + 1/2 (9.8)(3)²

s = 58.8 - 4.9 × 9

s = 58.8 - 44.1

s = 14.7 m