Question

An object is thrown vertically upwards with the speed v find the distance travelled in the 3rd second

Answer 1

$s = ut + 1 \div 2a {t}^{2}$
distance travelled in nth second=
$s = v + a \div 2(2n - 1)$
$h = v- g \div 2(2 \times 3- 1)$
=v-g/2(5)
=v-g/10