Question

an object is thrown with initial speed 5ms with an angle of projection 30.what is the height and range reached by the particle

Answer 1

an object is thrown with intial speed of 5m/s at an angle of projection 30° with the horizontal.

use formula , H = u²sin²∅/2g
here, ∅ is angle of projection with horizontal
u is the intial speed.
g is acceleration due to gravity.

now, H = (5² × sin²30°)/2 × 10
= (25 × 1/4)/20
= 25/80 = 5/16 m

range , R= u²sin2∅/g
R = 5² × sin60°/10
= 2.5 × √3/2
= 1.25√3 m

Answer 2

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Refer the attachment

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