Question

plz solve this question 29

Answer 1

mark the angle theta 1 , theta 2 ,theta 3
whose sum will be 180°
s = 14 + 50+ 48 /2
= 56
ar. ∆ = √ s(s-a )(s-b)(s-c)
= √ 56(56-14)(56-50)(56-48)
=√7×8×7×6×6×8
= 7×8×6
= 336

req. area = area of ∆ -3 area of sectors
= 336 - 3 ( theta1 + theta2+ theta3 /360) πr^2
=336- 3 (180/360)×22/7 ×5×5
=336 - 825/7
=336-117.85
=218.15 cm^2

Answer 2

218.15 cm^2 ...........................