Question

An Object mass 16kg is moving with an acceleration 3m/s2 calculate the applied force? If the same force is applied on an Object mass 24kg what will be the acceleration?

Answer 1

Answer:

f=ma

f=16×3=48newton

then the acceleration of another object is

a= f/m

• a=48/24= two

Explanation:

here the resultant acceleration of object is two

Answer 2

Answer:

• The acceleration (a₂) will be 2 m/s²

Given:

1. Mass of the First body (M₁) = 16 Kg
2. Mass of the second body (M₂) = 24 Kg
3. Acceleration of the First body (a₁) = 3 m/s²

Explanation:

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Case - 1

Applying, Newton's second law of motion

⇒ F = M₁ a₁

Here,

• F Denotes Force.
• M₁ Denotes Mass of first body.
• a₁ Denotes acceleration of first body.

Substituting the values,

⇒ F = 16 Kg × 3 m/s²

⇒ F = 16 × 3

⇒ F = 48

⇒ F = 48 N

∴ We got the value of applied force.

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Case - 2

Applying, Newton's second law of motion

⇒ F = M₂ a₂

Here,

• F Denotes Force.
• M₂ Denotes Mass of second body.
• a₂ Denotes acceleration of second body.

Substituting the values,

⇒ 48 N = 24 Kg × a

⇒ 48 = 24 × a

⇒ 48 = 24 a

⇒ 24 a = 48

⇒ a = 48 / 24

⇒ a = 2

⇒ a = 2 m/s²

∴ The acceleration (a₂) will be 2 m/s².

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