An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed? (Ans: 6 m/s) Solve the example.
Answers
Answered by
9
Hey friend here is ur solution.
_________________________
Total distance=( 18+22+14)m = 54m
Total time= (3+3+3)=9second
hence average speed=total distance/total time
= 54/9
= 6 m/s
_________________
Hope this will help......
_________________________
Total distance=( 18+22+14)m = 54m
Total time= (3+3+3)=9second
hence average speed=total distance/total time
= 54/9
= 6 m/s
_________________
Hope this will help......
Answered by
2
An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed? (Ans: 6 m/s)
solution : An object moves 18m in the first 3s, 22m in the next 3s and 14m in the last 3s.
total distance travelled = 18m + 22m + 14m
= 54 m
total time taken = 3s + 3s + 3s = 9s
average speed = total distance travelled/total time taken
= 54m/9s
= 6 m/s
hence, average speed of the object is 6m/s.
Similar questions