Question

An object moves along xaxis such that its position varying with time t is given by x=4t-t2 (xis in meter and time is in sec) the distance travelled by tge object frim t=0to t=3sec is

Answer 1

the total distance covered by object is 5 m

(0-2) sec :- 4 m covered

(2-3) sec. :- 1 m covered

total 5 m covered

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Answer 2

Answer:

The distance traveled by the object is 3 m.

Explanation:

Given that,

Position of the particle $x=4t-t^2$....(I)

Initial time = 0

Final time = 3 sec

We need to calculate the distance traveled by the object

Put the value of time in equation (I)

The distance at t = 0

$x_{0}=0$

The distance at t = 3 sec

$x_{3}=12-9=3\ m$

Now, The distance traveled by the object

$d=x_{3}-x_{0}$

$d=3-0=3\ m$

Hence,  The distance traveled by the object is 3 m.