Question

The numbers 4, 6, and 8 have the frequencies (x + 2), x and (x – 1), and if their arithmetic mean is 8, the value of x is​

Answer 1

Numbers are

4 , 6 , 8 , x+2 , x -1

Mean = 8

Mean = Sum of numbers / Number of terms

8 = 4 + 6 + 8 + x - 1 + x + 2 / 5

40 = 19 + 2x

x = 40 - 19 / 2

x = 21 /2

x = 10,5

hope it helped you

Answer 2

The value of x is 1.33.

Step-by-step explanation:

Since we have given that

Number          frequency

   4                      x+2

   6                        x

   8                       x-1

Arithmetic mean = 8

As we know that

$Mean=\dfrac{\sum fx}{\sum f}\\\\8=\dfrac{4(x+2)+6x+8(x-1)}{x+2+x+x-1}\\\\8=\dfrac{4x+8+6x+8x-8}{3x+1}\\\\8=\dfrac{18x}{3x+1}\\\\}8(3x+1)=18x\\\\24x+8=18x\\\\24x-18x=-8\\\\-6x=8\\\\x=\dfrac{8}{-6}=1.33$

Hence, the value of x is 1.33.

# learn more:

The numbers 4 and 9 have frequencies x and x-1 respectively . If their arithmetic mean is 6 then x=?

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