An object moves from A to D along a rectangular path , AB =10km, BC = 6km, what is the displacement of the object?
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The displacement of the object is the shortest distance covered by the object
hence ABCD is a rectangular path the displacement between point A and C is AC
SO AC=√(10^2+6^2)=12.89km
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hence ABCD is a rectangular path the displacement between point A and C is AC
SO AC=√(10^2+6^2)=12.89km
here is your required answer
hope this will help you my friend
you can follow me and mark as brainliest to get your answer thoroughly
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