Question

An object moves from A to D along a rectangular path as
shown in the given figure. Find:
a. the distance covered by the object,
b. the displacement of the object.​

Answer 1

Answer:

a. 26km

b. 6km

Explanation:

a.

opposite sides of triangle r equal

distance= ab+bc+cd

=10+6+10

26

b shortest or staright path is displacement

displacement= Ad

Ad = 6 ( opposute sides of triangles r equal)

Answer 2

Answer:

a. 26 km is covered by the object from A to D.

b. The displacement of the object is 6 km.

Explanation:

Since ABCD is a rectangle.

⇒ $AB = CD$ and $BC = AD$

Given: Object moves from A to D along a rectangular path such that AB = 10 km, BC = 6 km.

Also, CD = 10 km and AD = 6 km

a.

Distance covered by the object from A to D,

= dist. covered from A to B + dist. covered from B to C + dist. covered from C to D

= AB + BC + CD

= 10 + 6 + 10

= 26 km

Thus, 26 km is covered by the object from A to D.

b.

Displacement is defined as the shortest path from initial point to the final point.

So, A to D is the shortest path to reach point D form A.

Displacement = AD

                        = 6 km.

Thus, the displacement of the object is 6 km.

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