Question

an object moves from positions (6,8) to (12,10) in the x-y plane. Find the magnitude and direction of the displacement ​

Answer 1

Step-by-step explanation:

x = 3 sin 2t ∴ Vx = (dx / dt) = 6 cos 2t y = 3 cos 2t Vy = (dy / dx) = 6(– sin 2t) hence speed = V = √(Vx2 + Vy2) = √(62 cos2 2t + 62 sin2 2t) = 6(1) = 6 m/s

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