Physics, asked by chupekhoi, 10 months ago

An object moves in the xy-plane with coordinates:

x = 4cos(20 t) ( m)

and

y = 4sin(20 t) (m ) .

a/ Find the object’s distance from the the origin and the speed of the object at every instant of time. Deduce

the characteristics of this motion.

b/ Determine the magnitude and the direction of the acceleration vector at each instant of time.

c/ Sketch the trajectory of this object with the velocity vector and acceleration vector at some instant of time t.

Answers

Answered by rajivrtp
0

Explanation:

given

x= 4cos(20t)

y= 4sin(20t)

initially at= 0

x= 4cos(20×0)= 4×1= 4 m

y= 4sin(20×0)= 0

therefore the object is at 4 m distance from the origin in the positive direction on x- axis.

speed of the object,

dy/dt= 4× 20 cos(20t)

dx/dt= - 4×20sin(20)t

=> dy/dx= (dy/dt) / ( dx/dt)= -cos(20t)/sin(20t)

Vt= -cot(20t) m/s

acceleration= dVt/dt= 20cosec²(20t) m/s²

An sketch is attached.

Attachments:
Answered by AditiHegde
0

Given:

An object moves in the xy-plane with coordinates:  x = 4cos(20 t) ( m)  and  y = 4sin(20 t) (m ) .  

To find:

a/ Find the object’s distance from the the origin and the speed of the object at every instant of time. Deduce  the characteristics of this motion.

b/ Determine the magnitude and the direction of the acceleration vector at each instant of time.

c/ Sketch the trajectory of this object with the velocity vector and acceleration vector at some instant of time t

Solution:

From given, we have,

x = 4cos(20 t) ( m)  and  y = 4sin(20 t) (m )

Vx = dx/dt = -80 sin (20t) and Vy = dy/dt = 80 cos (20t)

Ax = dVx/dt = -1600 cos (20t) and Ay = dVy/dt = -1600 sin (20t)

a. The distance from origin,

d = √[x² + y²] = √[16 cos² (20t) + 14 sin² (20t)] = √16 = 4 m

The speed of the object,

Speed = √[Vx² + Vy²] = √[6400 sin² (20t) + 6400 cos² (20t)] = √6400 = 80 m/s

The characteristics of its motion,

The object is moving in a circular path having a radius of 4m moving in counter clockwise direction.

b. The magnitude and the direction of the acceleration

A = √[Ax² + Ay²] = √[(-1600)² cos² (20t) + (-1600)² sin² (20t)] = √1600² = 1600 m/s²

The acceleration is directed towards the origin/centre of the circle.

c. The trajectory of this object with the velocity vector and acceleration vector at some instant of time t is attached below.

Attachments:
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