Question

An object moves on a circular path such that the distance
covered is given by S = (0.5t2 + 2t) m, here t is time in s. If
radius of circle is 4 m, then initial acceleration of object is​

Answer 1

Explanation:

3m/s^2

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Answer 2

Answer:

S=(0.5t^2+2t)

differentiating w.r.t 't'

v= t+2

therefore initial velocity at t=0 is 2 m/s

again differentiating w.r.t 't'

a= 1

therefore centripetal acceleration= v^2/r

radius=4

=4/4 = 1

and initial acceleration = 1

applying vector sum on initial acceleration and centripetal acceleration = √(1^2+1^2)= √2 (ans)