an object moves through 100 m in 2 min and next 10 m in 3 min.Calculate its average speed
Answers
Answered by
13
distance 1 = 100 m
distance 2 = 10 m
time 1 = 2 min = 2×60 = 120 s
time 2 = 3 min = 3×60 = 180 s
avg speed
= (100+10)/(120+180)
= 110/300
= 11/30 m/s
distance 2 = 10 m
time 1 = 2 min = 2×60 = 120 s
time 2 = 3 min = 3×60 = 180 s
avg speed
= (100+10)/(120+180)
= 110/300
= 11/30 m/s
Answered by
13
Heya,
Given,
Distance 1 = 100m
Distance 2 = 10m
Total distance covered = 110 m
Time taken 1 =2m = 120 seconds
Time taken 2 = 3m = 180 seconds
Total time taken = 300 seconds
Average speed= Total distance covered/ Total time taken
=110m/300 sec
= 11/30 m/s
Hope it helps u.....
Given,
Distance 1 = 100m
Distance 2 = 10m
Total distance covered = 110 m
Time taken 1 =2m = 120 seconds
Time taken 2 = 3m = 180 seconds
Total time taken = 300 seconds
Average speed= Total distance covered/ Total time taken
=110m/300 sec
= 11/30 m/s
Hope it helps u.....
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