Question

An object moves with a constant acceleration of 5 m/s2. Which of the following statements is true?

(1 Point)

a. The object’s velocity stays the same

b. The acceleration increases by 5 m/s2 each second

c. The object moves 5 m each second

d. The object’s velocity increases by 5 m/s each second​

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

An object is moves with a constant acceleration of 5 m/s².

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

Which of the given statement is true.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

◈ What is acceleration :

❅ Acceleration is defined as the rate of change of velocity.

❅ It is a vector quantity having both magnitude as well as direction.

❅ SI unit : m/s²

Formula :

$\dag\:\:\boxed{\bf{\purple{a=\dfrac{v-u}{t}}}}$

Let initial velocity of moving object with acceleration of 5 m/s² be u and final velocity after 1s be v.

$:\implies\tt\:a=\dfrac{v-u}{t}$

$:\implies\tt\:5=\dfrac{v-u}{1}$

$:\implies\tt\:v-u=5$

$:\implies\boxed{\bf{\gray{v=u+5}}}$

✼ It means velocity of moving object increases by 5m/s each second.

Answer 2

Answer:

Given:

An object is moves with a constant acceleration of 5 m/s².

ToFind:

Which of the given statement is true.

Solution:

◈ What is acceleration :

❅ Acceleration is defined as the rate of change of velocity.

❅ It is a vector quantity having both magnitude as well as direction.

❅ SI unit : m/s²

Formula :

\dag\:\:\boxed{\bf{\purple{a=\dfrac{v-u}{t}}}}†

a=

t

v−u

Let initial velocity of moving object with acceleration of 5 m/s² be u and final velocity after 1s be v.

:\implies\tt\:a=\dfrac{v-u}{t}:⟹a=

t

v−u

:\implies\tt\:5=\dfrac{v-u}{1}:⟹5=

1

v−u

:\implies\tt\:v-u=5:⟹v−u=5

:\implies\boxed{\bf{\gray{v=u+5}}}:⟹

v=u+5

✼ It means velocity of moving object increases by 5m/s each second.