Question

An object moving at a speed of 5m/s accelerates uniformly at a rate of 3 m/s2
.

Calculate the distance covered in 8 seconds?

Answer 1

if you circulated and object moving at a speed of 5 metre per second square accelerated uniformly at a rate of 3 metre square to square you need to apply the rule v is a square is equal to square + 2 y s r s is equal to UT plus half a t square

Answer 2

Answer:

136m

Explanation:

initial velocity (u) = 5m/s

acceleration (a) = 3m/s^2

time (t) = 8 seconds

distance(s) = ?

[ S = UT + 1/2 AT^2]

    = (5 x 8) + ( 1/2 x 3 x 8^2)

    = 40 + 96

    = 136m

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