Question

an object moving to the right has a decrease in velocity from 5.0 m/s to 1.0m/s in 2.0 s what is the average acceleration? what does your result mean?
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Answer 1

$\large{\underline{\underline{\red{\sf{\hookrightarrow Given:- }}}}}$

• An object moving to the right has a decrease in velocity from 5.0 m/s to 1.0m/s in 2.0 s

$\large{\underline{\underline{\red{\sf{\hookrightarrow To\:Find:-}}}}}$

• Average acclⁿ .

$\large{\underline{\underline{\red{\sf{\hookrightarrow SolUtion:-}}}}}$

We know that the rate of change of velocity is called acceleration . So

$\sf:\implies\pink{ a =\dfrac{\Delta v }{t}}\\\\\sf:\implies a =\dfrac{ 5-1 }{2} m/s^2\\\\\sf:\implies a =\dfrac{4}{2} m/s^2 \\\\\sf:\implies \underset{\blue{\sf Required\ Answer}}{\underbrace{\boxed{\pink{\frak{ Acceleration = 2 m/s^2}}}}}$

Answer 2

Given info : An object moving to the right has a decrease in velocity from 5.0 m/s to 1.0m/s in 2.0 s.

To Find : Average Acceleration .

Solution :

We know acceleration as rate of change of velocity . So ,

=> a = v-u /t

=> a = 5-1/2

=> a = 4/2

=> a = 2m/s²