Question

An Object Moving With 6M Per Second Execute An Acceleration 2M Per Second Square In Next 3 Second . How Much Distance It Coverd.

Answer 1

As initial velocity U = 6m/s

As acceleration A = 2m/s²

As time T = 3

Let's find the distance S = UT + $\huge\frac{1}{2}$ A(T)²

S = 6 × 3 + $\huge\frac{1}{2}$ × 2 × 3²

S = 18 + 9

distance S = 27m

Answer 2

The object, therefore, covered 27 m.

Given:

The object's acceleration is 2 m/s².

The time that the object was moving, t = 3 sec.

Solution:

Step 1: Applying the equation of motion, determine how far the object has travelled:

Having said that,

Distance (s) = ut + 1/2²  

When we change the specified values in the equation, we obtain:-

=6×3+1/2(2)(3)

=18+12(2)(9)

=18+(9)

=27 m

The object, therefore, covered 27 m.

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