Question

an object moving with 90km/hr acceleration by 2m/s² . find its velocity after 10 second . can you explain me briefly​

Answer 1

Explanation:

Speed = 90 km/hr (u)

Acceleration = 2 m/s² (a)

Time = 10 seconds (t)

$\rightarrow$ v = u + at

$\rightarrow$ v = 90 + (2)(10)

$\rightarrow$ v = 90 + 20

$\rightarrow$ v = 70 kmph

The velocity is 70 kmph.

Answer 2

Answer:

Let u=90km/hr=25m/s

a=2m/s^2 and t=10 sec. and velocity after 10 seconds=?(v=?)

we know,

v=u+at

v=25+2×10

v=25+20=45m/s

Therefore,the velocity after 10 seconds is 45m/s.

now covert 45m/s in terms of km/hr,

v=45×18÷5=162km/hr.

Explanation:

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