Physics, asked by sharukh3812, 1 month ago

an object moving with velocity of 20m/s and suddenly increase the velocity up to 40m/s in just 5 seconds. Calculate accerleration.

Answers

Answered by MathLoverHannu
17

Answer:

Acceleration= 4m/s^2

Explanation:

 \tt \huge \red{༒︎To \:  \:   Fɪɴᴅ:-}

• Acceleration ( a )

 \tt \huge \red{༒︎Given:-}

• Initial velocity of object = 20m/s ( u )

• Final velocity = 40m/s ( v )

• Time = 5 seconds ( t )

 \tt \huge \red{༒︎ Formula:-}

 \tt Acceleration ( a ) =  \frac{ \: v \:  -  \: u}{t}

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 \to \tt a =  \frac{40 - 20}{5}  \\  \tt \to a =  \frac{20}{5}  \:  \: m {s}^{ - 2}  \\  \tt \to a = 4 \frac{m}{ {s}^{2} }  \:  \: or \: \:  4m {s}^{ - 2}

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