an object of 10 cm is placed at 30 cm infront of a convex lens of power 5D . claulate position, size and nature of image
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Step-by-step explanation:
Given:u=−10cm f=20cm (convex lens)
To find: v and image's nature.
Solution: From lens formula
v
1
−
u
1
=
f
1
v
1
+
10
1
=
20
1
v
1
=
20
−1
v=−20cm
And magnification =
u
v
=2
Hence image formed is virtual, erect and magnified two times.
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