an object of 100 gram is dropped from a tower of height 5 M calculate its Momentum when it touches ground G= 10 M /s²
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Given -
mass- 0.1 kg
Height- 5metre
G- 10 m/s^2
sol.—
momentum= mv
that is p=mv
using 3rd eqn of motion
2as=v^2-u^2
2*10*5=(v^2) -(0^2)
100=v^2
therefore v= 10 m/s
p=mv
p=0.1*10
p=1 kgm/s
mass- 0.1 kg
Height- 5metre
G- 10 m/s^2
sol.—
momentum= mv
that is p=mv
using 3rd eqn of motion
2as=v^2-u^2
2*10*5=(v^2) -(0^2)
100=v^2
therefore v= 10 m/s
p=mv
p=0.1*10
p=1 kgm/s
curiouslearner23yug:
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superscript
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??
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