An object of 15 cm is placed at 50cm in front of convex mirror of focal length 10 cm find the position nature and size of the image form also draw a ray diagram of it
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Values Given
u = -50 cm
f = -10 cm
h = 15 cm
v = ?
h' = ?
m = ?
So Firstly According to mirror formula,
1/v+1/u=1/f
1/v-1/50=-1/10
1/v = 1/50 - 1/10
v = -50/4 = -25/2 = -12.5 cm
So, the image is formed between focus and centre of the curvature
Now magnification, m produced by the mirror is -v/u
= -(-12.5)/(-50) = -1/4
Negative Sign shows that the image is formed is real and inverted
Now size of the image, h' = m*h
= -1/4*15 = -3.75 cm
Negative Sign shows that the mage formed is face downwards or inverted.
I cant draw ray diagram
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