Question

An object of 3 cm length is placed at 10 cm from the pole of a concave mirror of focal length 9 cm. What will be the size and position of the image?

Answer 1

by mirror formula
1/f =1/v+1/u
where f- focal length
v- image distance
u- object distance
1/9=1/v+ 1/10
1/v= 1/9
v=9
Soo the image formed at focus
by magnification
-v/u= Hi/ Ho
Hi- height of image and Ho- height of object
-9/10= Hi/3
Hi= -2.7
note size and height are same
"-" tells image formed below principal axis
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