an object of 4.0 cm in size is placed at 25 cm in front of concave mirror of focal length 15cm,find the image distance, nature and the size of the image
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since the lens is concave values of f , v , u are in negative
So, -1/15 = -1/25 -1/v
i/v = 1/15 - 1/25 = 5 - 3 / 75
v = 37•5.
size of image = 37•5 × 4/25 = 6cm .
Nature of image virtual erect enlarged
So, -1/15 = -1/25 -1/v
i/v = 1/15 - 1/25 = 5 - 3 / 75
v = 37•5.
size of image = 37•5 × 4/25 = 6cm .
Nature of image virtual erect enlarged
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