An object of height 4 cm is placed at a distance of 15 cm in from concave lens of power -10 dioptres, find size of the image? Class 10 science ch 10 solve it with proper explanation.
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Concave lens
ho=+4 cm
u=-15 cm
P=1/f f=Focal Length
-10 =1/f
f=(1/-10)×100 cm
f=-10cm
using lens formula
1/f=1/v-1/u
⇒1/v=1/f+1/u
⇒1/v= -1/10 -1/15
⇒1/v=(-3-2)/30
⇒1/v=-5/30
⇒1/v=-1/6
Image distance (v)= -6 cm
hi/ho=v/u
⇒hi=v/u×ho
⇒hi=-6/-15 ×4
⇒hi=2/5 ×4
⇒hi=8/5cm
⇒hi=1.6 cm
Image Height =1.6 cm Answer.
ho=+4 cm
u=-15 cm
P=1/f f=Focal Length
-10 =1/f
f=(1/-10)×100 cm
f=-10cm
using lens formula
1/f=1/v-1/u
⇒1/v=1/f+1/u
⇒1/v= -1/10 -1/15
⇒1/v=(-3-2)/30
⇒1/v=-5/30
⇒1/v=-1/6
Image distance (v)= -6 cm
hi/ho=v/u
⇒hi=v/u×ho
⇒hi=-6/-15 ×4
⇒hi=2/5 ×4
⇒hi=8/5cm
⇒hi=1.6 cm
Image Height =1.6 cm Answer.
harishdevkishan:
I think it should be -1.6 how it came +1.6
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