Question

an object of 4 cm height is placed at 15 CM in front of a concave mirror of focal length and screen be placed to obtain a sharp images calculated the height of the images​

Answer 1

Answer:

The formula related to focal length F, object to mirror distance u and image to mirror distance v is given by

Explanation:

1 1 1

_ + _ = _

v u f

1 1 1

_ + _ = _

v 15 10

solving for v, we get v = 30 cm

magnification = v/u = -30/15 = -2

image size = -2×4 = -8cm (negative sign indicates image is inverted)

Answer 2

Answer:

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