Question

An object of 40 kg is raised to a height of 10 m above the ground. What is its Kinetic energy when it is half way down?

Answer 1

$\huge\boxed{Answer}$

Mass of the object, M=40kg

Height up to which it is raised h=5 m

Potential energy P.E=Mgh

P.E=40×10×5=2000J

Let its kinetic energy be Ek when it is halfway down i.e h′=h/2

According to the conservation of energy,

K.Ei+P.Ei=K.Ef+P.Ef

0+2000=Ek+Mgh/2

∴ 2000=Ek+40×10×5/2

⟹Ek=1000J

$\huge\mathfrak\red{itz\:jyotsana☺}$

Answer 2

$\huge{\bold {\underline \red{Hlw}}}$

$\star \: \: {\blue{\underline {Given }} \blue: }$

• Mass of object = 40 kg
• Hight = 10 m

$\star \: \: {\blue{\underline {Solution}} \blue: }$

• Loose of Potential Energy = Gain of Kinetic Energy

Loose of Potential Energy,

mgH - mgh

=mg(10-5) J

=40×10×5 J

=2000 J

///MARK IT BRAINLIEST///