Question

an object of 40kg is raised toa height of 5m above the ground what is its potential energy?if the object is allowed to fall ,find its kinetic energy when it is half way down

Answer 1

[take g=10m/s]
P.E.=mgh=>40(10)(5)=2000J
K.E. at h/2=P.E. at h/2=(40)(10)(2.5)=>(40)(25)=1000J

.: ans.=[P.E.=2000J]; [K.E.=1000J]

Answer 2

_/\_Hello mate__here is your answer--

_______________________

Given:-

m = 40 kg

g = 9.8 m/s^2

h = 5 m

We know that,

potential energy = mgh

= 40 × 9.8 × 5 J

= 1960 J

_______________________

♦♦The total mechanical energy (Kinetic and potential energy) of an object remains constant. (law of conservation of energy)

Therefore, when the object is half-way down, its potential energy become half the original energy and remaining half converted into kinetic energy.

Hence, the kinetic energy = ½ (1960) J = 980 J

I hope, this will help you.☺

Thank you______❤

_________________________❤