Question

An object of 5 cm is placed at a distance of 10 cm in front of a bi-concave lens of focal length 15 cm . Calculate the size and position of the image and also comment on the nature of the image

Answer 1

Explanation:

h o= +5 cm

h i = - \10 cm

f = -15 cm

1/f = 1/v - 1/u

1/v = -1/15 - 1/10

1/v = (-2-3)/30 = -5/30 = -1/6

v = -6 cm

m = v/u= 6/10 = 3/5

m= h i / h o

3/5 = h i / 5

h i = 3 cm

Therefore, the image formed is virtual, diminished, and erect.It is present at 6cm in front of the lens, and is 3 cm in height.

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