Question

an object of 5cm kept front of a concave mirror of focal length 15 cm at 25 cm. find the position of image ,nature of image and size of the image. ​

Answer 1

Answer: V= 0.027cm

Explanation:

from mirror formula,1/f=1/v+1/u

1/15= 1/25+I/V

V= 0.027cm

Then magnification (M) = v/u

M = 0.027cm/25cm = 0.001

Also,M = hi/ho

0.001 = hi/ 5cm

hi = 0.005 cm

Therefore, the image formed is real, 0.005cm high(diminished) and inverted image