An object of 5cm placed infront of a concave mirror at 30cm which focal length is 10cm Find the position size and nature of image formed also draw the ray diagram
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Answer:
h' = -1
Explanation:
Object distance , u= -60cm
Focal lenght , f =-10cm
Object size = 5 cm
v =?
Mirror formula,
1/v + 1/u = 1/f
1/v = 1/u - 1/f
1/v= 1/-(60) +1/-(10)
1/v = -1+6/60
1/v = -5/60
1/v = -1/12
v = -12
Image position = -12
Size of the image,
Magnification , m= -v/u
m = -(-12)/-60
m = 12/-60
m = 1/-5
m= -0.2
Then ,
m = h'/h
-0.2= h'/5
-0.2 × 5 = h
h' = -1
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