Question

An object of 5cm size placed at a distance of 20 cm from a converging of focal length 15 CM at what distance from the mirror should be screened at a place together image also today size of the mirror

Answer 1

Answer:

h1 = 5.0cm, u = -20cm, f = -15cm, v =?, h2 = ?

We know that

1/v + 1/u = 1/f

1/v + 1/(-20) = 1/(-15)

1/v = 1/20 – 1/15

1/v = -5/300

V = -60 cm

The screen should be placed 60 cm in front of the mirror.

And,

m = h2/h1 = - (v/u)

h2/5 = - (-60)/(-20)

h2 = - 15 cm

height of image = 15cm

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