An object of 5kg mass is placed on a cylindrical stand having circular cross section. The radius of the base of the stand is 4cm. If the same object is placed on cylindrical stand with radius of the base of stand 2cm,the pressure becomes :
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p=f/area
p=5kg/2cm
p=5×100 kg/2m
p=500kg/2m
p=250ķg/m
p=250 Pascal
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p=5kg/2cm
p=5×100 kg/2m
p=500kg/2m
p=250ķg/m
p=250 Pascal
hope it helped
Plz mark me as brainliest
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