Question

An object of height 1.2 metre is placed before a concave mirror of focal length 20 CM so that a real image please format at a distance of 60 centimetre from it find the portions of and object what will be the height of the image format

Answer 1

f=-20cm

h=1.2m=1,20cm

v=-60cm

1/v+1/u=1/f

-1/60+1/u=-1/20

1/u=-1/20+1/60

1/u=(-3+1)/60

1/u=-2/60

1/u=-1/30

u=-30cm

h'/h=-v/u

h'/120=-(-60/-30)

h'/120=-1/2

h'=(-1/2)x120

h'=-60cm

height of image=real and inverted

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Answer 2

height of the object  = 1.2m = 120cm

f =- 20cm

v =-60cm

1/v+1/u =1/f

1/u = 1/f - (-1/v)

      -1/20 + 1/60   = -2/60

u = -30cm

-v/u = height of the image / height of the object

       =      - (-30)/-20 = height of the image / 120

        =  -180 cm

Height of  the  image =  - 180cm (Real and Inverted )