Physics, asked by rohit2875, 1 year ago

An object of height 1 cm is kept perpendicular to the principal axis of a convex mirror of radius of
curvature 20 cm. If the distance of the object from the mirror is 20 cm then the distance (in cm) between
heads of the image and the object will be:

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Answers

Answered by astha1069
15
40/3 is the distance between head of the image and object we use the mirror Formula
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astha1069: am i right
rohit2875: no sorry Ist option is correct answer
Answered by phillipinestest
8

Answer:

The distance between image and object is -\frac {40} {3}.

Given is the value of f as f = 10 cm and the u is u = 20 cm and will be taken negative as a case of convex lens.

Therefore the formula be used,

\frac {1} { f} = \frac {1} {u} + \frac {1} {v}

=>\frac {1} {10} = -\frac {1} {20} + \frac {1} {(- v)}

=>\frac {1} {10} = \frac {-1} {20} - \frac {1} {v}

=> \frac {1} {v} = -\frac {1} {20} - \frac {1} {10}

=> v = -\frac {20} {3}.

Therefore the distance between the object and image is,

                       2 v = 2 x -\frac {20} {3} = -\frac {40} {3}.

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