Question

an object of height 10 cm is placed at a distance of 25 cm from a concave lens of focal length of 20 cm.Find position,height and nature of image to give figure

Answer 1

H = 10 cm

U= -25 cm

f= -20 cm

1÷f=1÷U + 1÷V

-1÷20 = 1÷-25 + 1÷v

-1÷20+1÷25=1÷V

ON TAKING LCM

[-5+4]÷25 = 1÷V

-1÷25 = 1÷V

ON TAKING RECIPROCAL

V =  - 25 CM

THEREFORE........the image is formed on the same side of the object , virtual and errect ......

HOPE IT HELPS....!!!!!!!