Question

an object of height 2.5 cm is placed at a distance of 15 cm from the optical centre of of a convex lens of focal length 10cm ray diagram to find the position and size of the image formed work optical centre of principal focus and height of the image on the diagram

Answer 1

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Answer 2

Answer:

Explanation:

Given :-

h = 2.5 cm

u = - 15 cm

f = + 10 cm

Solution :-

Using, 1/v - 1/u = 1/f, we get

1/v = 1/f + 1/u

⇒ 1/v = 1/10 - 1/15

⇒ 1/v = 15 - 10/150

⇒ 1/v = 5/150

⇒ v = 30 cm

h'/h = v/u

⇒ h'/2.5 = 30/- 15

⇒ h' = - 5 cm

Hence, The height is 5 cm, and is enlarged.