An object of height 2.5 cm is placed at a distance of 15 cm from the optical centre of a convex lens of focal length 10 cm draw a ray diagram to find position and size of image formed mark optical centre O of principal focus F and height of image on the diagram.?
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9
h = 2.5
u= -15
f = 10
1/f = 1/v - 1/u
1/10 = 1/v - 1/-15
1/10 +1/-15 = 1/v
-15+10/10×-15 = 1/v
-5/-150 = 1/v
30 = v
m= -v/u
m = -30/-15
m = 2
m = h2/h1
2×2.5 = h2
5 = h2
i hope this is it's answer
u= -15
f = 10
1/f = 1/v - 1/u
1/10 = 1/v - 1/-15
1/10 +1/-15 = 1/v
-15+10/10×-15 = 1/v
-5/-150 = 1/v
30 = v
m= -v/u
m = -30/-15
m = 2
m = h2/h1
2×2.5 = h2
5 = h2
i hope this is it's answer
anjali288:
no answer will be in minus
Answered by
9
Hii,
If it helps mark as the brainliest
Thanks xD xD
If it helps mark as the brainliest
Thanks xD xD
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