An object of height 2 cm is placed at a distance of 30 cm from a convex lens of focal length 10
cm. Find the position, nature and height of the object.
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height of object=2
1/f=1/v-1/u
1/10=1/30-1/-u
1/10-1/30=1/u
2/30=1/u
1/15=1/u
u=15cm
v/u=h of object /height of images
30/15=2/h
h=1cm
nature of image diminished,virtual,erect
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