an object of height 2 cm is placed at a distance of20 cm in front of a concave mirror of focal length 12 cm . find the position , size and nature of the image.
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given ,
focal length (f ) = - 12 cm
object distance ( u ) = -20 cm
use formula ,
1/u + 1/ v = 1/ f
1/(-20) + 1/v = 1/(-12)
1/v = 1/20 - 1/12
=-8/20 x 12 = - 1/30
v = - 30 cm
hence image form 30 cm distance from the pole of mirror from left side .
m = -v/u = height of image / height of object
-(-30)/(-20) = height of image /2 cm
height of image = -3 cm
hence image form left side from the pole below the x -axis and image is real inverted and larger then object .
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