If x=3 is one root of the quadratic equation xsqaure-2kx-6=0 find the value of k
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If x=3 is a root,
x²-2kx-6=0
3²-2k(3)-6=0
9-6k-6=0
-6k= -3
k=1/2
x²-2kx-6=0
3²-2k(3)-6=0
9-6k-6=0
-6k= -3
k=1/2
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