Question

An object of height 20 cm is kept at a distance of 48cm in front of a mirror of focal length 12cm. Find the distance of the image from the mirror and its magnification​

Answer 1

Answer:

The distance of the image from mirror and its magnification is 9.6 cm and 0.2 respectively.

Step-by-step explanation:

Given that,

Height of the object, h = 20 cm

Object distance, u = -48 cm

As it forms virtual ,diminished image of the object, this is a case of convex mirror, so, f = +12 cm

Let v is the location of the image. It can be calculated as :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

v

1

+

u

1

=

f

1

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

v

1

=

f

1

−

u

1

\dfrac{1}{v}=\dfrac{1}{12}-\dfrac{1}{(-48)}

v

1

=

12

1

−

(−48)

1

v = 9.6 cm

So, the image will be formed at a distance of 9.6 cm from the mirror. The magnification of the mirror is given by :

m=\dfrac{-v}{u}m=

u

−v

m=\dfrac{-9.6}{-48}m=

−48

−9.6

m = 0.2

I hope it helps....

If anything is wrong then sorry....