an object of height 2cm is at a distance of 15cm infront of a concave lens of power -10D find the image size
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Answer:
img size(Ho) = 5 cm
Explanation:
Power of lens(D) = 1/focal length(m)
thus f = 1/-10 = - 0.1 m = - 10 cm
Lens Formula
1/f = 1/v - 1/u
thus 1/v = 1/-10 + 1/-15
= (-3-2)/15 = -6 cm
Hi / Ho = v / u
Ho = Hi * u / v
= 2 * (-15)/(-6)
= 5 cm
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