Question

An object of height 3cm is placed in front of a convex mirror of focal length 6cm at a distance of 18cm. Find the position of the image,height of the image formed,magnification produced,interpret the result,draw a ray diagram

Answer 1

Focal length(f) = 10 cm.

Object distance(u) = 15 cm.

Height of the Object = 6 cm.

Using the Mirror's formula,

1/f = 1/v + 1/u

⇒ 1/-10 = 1/v + 1/-15

⇒ 1/v = 1/-10 + 1/15

∴ 1/v = (-3 + 2)/30

⇒ v = -30 cm.

Since, image distance is negative, therefore, it is real and inverted.

Now, magnification = -v/u

= -(-30)/15

= 2

Since, magnification in greater than 1, therefore Image is magnified.

Also, m = H of image/H of object.

⇒ 2 = H of image/6

∴ Height of image = 12 cm.

Characteristics of Image are ⇒

Real, Inverted and Magnified.

Hope it helps.

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