find area of triangle whose vestices are (2,7),(1,1),(10,8)
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formula of triangle: base times height divided by 2
1) 2 times 7=14 divide by 2=7
2)1 times 1=2 divide by 2=1
3)10 times 8=80 divide by 2=40
plz mark brainliest and hope it helps!!
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Answer:
(x₁y₁)=(2,7);(x₂y₂)=(1,1);(x₃y₃)=(10,8)
Step-by-step explanation:
area of triangle=x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)
2(1-8)+1(8-7)+10(7-1)
-14+1+60=47
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