Question

An object of height 4 cm is placed at a distance of 20 CM in front of a lens of focal length 10 cm which always forms virtual image. Find image position, height of image, nature of image


I will mark the best answer brainliest....​

Answer 1

Answer:

Starting from a large value, as the object distance decreases (i.e., the object is moved closer to the lens), the image distance increases; meanwhile, the image height increases. At the 2F point, the object distance equals the image distance and the object height equals the image height.

Explanation:

When we stand close to a concave mirror, our image will be virtual, enlarged and erect. Explanation: (a) When we stand close to a large convex mirror, our image will be diminished, erect and virtual because the object lies between the infinity and the pole.

Answer 2

This is a Magnifying Glass, so expect erect enlarged virtual image.

please mark me as brainliest