Question

an object of height 4cm is placed at a distance of 15cm from a converging lens of focal length 10cm find the position nature and height of image?​

Answer 1

Answer:

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Explanation:

u=−10cm

h

1

=4cm

f=20cm

v

1

−

u

1

=

f

1

v

1

−

−10

1

=

20

1

v

1

=

20

1

−

10

1

=−

20

1

v=−20cm (Image is 20cm in front of the convex lens)

m=

u

v

=

−10

20

=−2

m=

h

1

h

2

=−2

4

h

2

=−2

h

2

=−8cm

Image is 8cm in size and is real and inverted .