Question

an object of height 5 cm is kept in front of concave mirror at a distance of 15 cm. if the real image is formed at a distance of 25 cm from the mirror claculate focal length of mirror​

Answer 1

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Answer 2

Answer:

u=-5 cm, f=10 cm

We know that

v

1

+

u

1

=

f

1

⇒

v

1

+

(−5)

1

=

10

1

⇒

v

1

=

20

1

+

5

1

=

10

3

∴v=

3

10

cm=3.33cm

The position of the image is 3.33 cm behind the convex mirror.

Magnification, m=−

u

v

=−

−5

3.33

=0.66

The image is virtual and erect.

Explanation:

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